Question # 1

When an operator function is defined as member function for a binary Plus (+) operator then the number of argument it take is/are

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Zero

One

Two

N arguments

The prototype of friend functions must be written ____ the class and its definition must be written ____.

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inside, inside the class

inside, outside the class

outside, inside the class

outside, outside the class

When an object of a class is defined inside another class then,

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Destructor of enclosing class will be called first

Destructor of inner object will be called first

Constructor and Destructor will be called simultaneously

None of the given options

Which of the following is the correct C++ syntax to allocate space dynamically for an array of 10 int?

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new int(10)

new int[10] ;

int new(10) ;

int new[10];

What does STL stand for?

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Source template library

Standard template library

Stream template library

Standard temporary library

The code is written to __________ the program.

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implement

design

analysis

none of the given options

Disks are _______________ devices having access time of _________ milliseconds

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Electro-physical, 6

Electro-Mechanical, 4

Electro-physical, 5

Electro-Mechanical, 7

If there is a symbol (& sign) used with the variable name followed by data type then it refers to _____ and if & is being used with variable name then it refers to _____.

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Address of variable, reference variable

Reference variable, value of variable

Reference variable, address of variable

Address of variable, value of variable

&& is -------------------- operator.

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An arithmetic

Logical

Relational

Unary

Which of the following statement is best regarding declaration of friend function?

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Friend function must be declared after public keyword

Friend function must be declared after private keyword

Friend function must be declared at the top within class definition

It can be declared anywhere in class as these are not affected by the public and private keywords

Which of the following is NOT a preprocessor directive?

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#error

#define

#line

#ndefine

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