1 |
A business cycle has |
one phase
two phases
three phases
four phases
|
2 |
Which one is a rough and crude method for measuring secular trend ? |
free hand curve method
semi average method
moving averages method
least square method
|
3 |
Methods of semi-averages gives an |
accurate result
objective result
authentic result
none of these
|
4 |
The method of least square gives too much weight to extremely large deviations from the |
population
parameter
sample
trend
|
5 |
Sum of squares of residuals is denoted by |
∑<i>e</i>
∑<i>e</i><sup>2</sup>
∑<i>e</i><sup>3</sup>
<span style="font-size: 14.399999618530273px;">∑</span><i style="font-size: 14.399999618530273px;">e</i><sup>4</sup>
|
6 |
The elimination or addition of a few more time periods may change its |
speed
value
direction
none of these
|
7 |
The least squares estimates are unbiased estimates of the |
statistic
time series
parameters
variance
|
8 |
The straight line is fitted to a time series when the movements in the time series are |
linear
quadratic
cubic
constant
|
9 |
In the measurement of secular trend the moving averages |
give the trend in a straight line
measure the seasonal variations
smoothes out a time series
measure irregular fluctuations
|
10 |
The secular trend is measured by the method of semi-averages when |
time series contains yearly values
trend is linear
time series contains odd number of values
none of these
|
11 |
The graph of a time series is called |
histogram
polygon
straight line
historigram
|
12 |
The sample size n is reasonably large so that for each cell, the estimated expected frequency must be at least |
2
3
4
5
|
13 |
When the expected frequencies are very small the value of=χ2has been |
adjusted
omitted
changed
all of these
|
14 |
If any ultimate class frequency is negative the data will be |
inconsistent
consistent
correlated
composite
|
15 |
The critical region of=χ2distribution is |
χ2 <χ2v; 1-α
χ2 <χ2v;1-α
χ2 <χ2 v;1-α/2
χ2 <χ2v;1-α/2
|
16 |
The value of coefficient of association lies between |
0 and + 1
-1 and + 1
-1 and 0
-0.5 and + 0.5
|
17 |
(α) = (αB) + ------------------ |
(Aβ)
(AB)
(αβ)
(A)
|