ICS Part 2 Statistics Online Test With Answers

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ICS Part 2 Statistics Online Test

Sr. # Questions Answers Choice
1 A business cycle has one phase two phases three phases four phases
2 Which one is a rough and crude method for measuring secular trend ? free hand curve method semi average method moving averages method least square method
3 Methods of semi-averages gives an accurate result objective result authentic result none of these
4 The method of least square gives too much weight to extremely large deviations from the population parameter sample trend
5 Sum of squares of residuals is denoted by ∑<i>e</i> ∑<i>e</i><sup>2</sup> ∑<i>e</i><sup>3</sup> <span style="font-size: 14.399999618530273px;">∑</span><i style="font-size: 14.399999618530273px;">e</i><sup>4</sup>
6 The elimination or addition of a few more time periods may change its speed value direction none of these
7 The least squares estimates are unbiased estimates of the statistic time series parameters variance
8 The straight line is fitted to a time series when the movements in the time series are linear quadratic cubic constant
9 In the measurement of secular trend the moving averages give the trend in a straight line measure the seasonal variations smoothes out a time series measure irregular fluctuations
10 The secular trend is measured by the method of semi-averages when time series contains yearly values trend is linear time series contains odd number of values none of these
11 The graph of a time series is called histogram polygon straight line historigram
12 The sample size n is reasonably large so that for each cell, the estimated expected frequency must be at least 2 3 4 5
13 When the expected frequencies are very small the value of=χ2has been adjusted omitted changed all of these
14 If any ultimate class frequency is negative the data will be inconsistent consistent correlated composite
15 The critical region of=χ2distribution is χ2 &lt;χ2v; 1-α χ2 &lt;χ2v;1-α χ2 &lt;χ2 v;1-α/2 χ2 &lt;χ2v;1-α/2
16 The value of coefficient of association lies between 0 and + 1 -1 and + 1 -1 and 0 -0.5 and + 0.5
17 (α) = (αB) + ------------------ (Aβ) (AB) (αβ) (A)
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