1 |
In which quadrant is the solution of the equation sin x - 1 = 0 |
II quadrants
II and III quadrants
III and Iv quadrants
I quadrant
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2 |
Cos-1 x = |
∏ = sin<sup>-1</sup> x
∏ + sin<sup>-1</sup> x
∏/2 - sin<sup>-1</sup> x
∏/2 +sin<sup>-1</sup> x
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3 |
Sec-1 x= |
Cos<sup>-1</sup> 1/x
Cosec<sup>-1</sup> 1/x
Cos-1 (-x)
Tan<sup>-1</sup> x
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4 |
Sin-1 (-x) = |
Cos<sup>-1</sup> 1/x
-Sin<sup>-1</sup> X
1/sin-1x
Sin<sup>-1</sup> 1/x
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5 |
Tan-1 1/x =______ |
Sin x
Sec<sup>-1</sup> X
Cot<sup>-1</sup> X
Sin Ix/cos- Ix
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6 |
Sin-1 [-1/2] = ______. |
∏/3
-∏/6
-∏/3
∏/6
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7 |
If Cosθ =0, Then θ= |
nπ/2
(2n + 1)π/2
(2n - 1)π/2
(n ±1)π/2
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8 |
In the figure angle A is = |
15
60
90
20
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9 |
If you looking a high point from the ground then the angle formed is |
Angle of elevation
Angle of depression
Right angle
Horizon
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10 |
Area of ΔABC= |
ab sin α
1/2 ab sin α
1/2 ac Sin γ
1/2 ac Sin β
|