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Online Tests
Ics Part 2 Physics Chapter 7 Test Online MCQs With Answers
Question # 1
In an N-type silicon, which of the following statement is true?
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Electrons are majority carriers & trivalent atoms are the dopants
Electrons are majority carriers & pentavalent atoms are the dopants
Holes are minority carriers & pentavalent atoms are the dopants.
Holes are minority carriers & trivavalent atoms are the dopants.
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Question # 2
When a PN-Junction is reverse biased the depletion region is.
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Widened
Narrowed
Normal
None of these
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Question # 3
Reverse current flows due to
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Majority charge carriers
Minority charge carriers
Electrons
Holes
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Question # 4
The potential difference across depletion region in case of Si is
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0.6 volt
0.9 volt
0.7 volt
0.2 volt
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Question # 5
The impurity in the germinium is usually in the ratio of
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1:10
6
1:10
4
1:10
8
1:10
10
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Question # 6
The average gap for Germanium at 0K is
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1.12 ev
0.02 ev
6.72 ev
7.2 ev
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Question # 7
In photovoltaic cell, current is directly proportional to.
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Wavelength of light
Intensity of light
Energy
Frequency of light
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Question # 8
The P.D develop in case of germanium is:
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0.3
0.7
0.5
0.9
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Question # 9
Transistor was discovered by
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Young
Curie
John Bardeen
Shale's
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Question # 10
In case of op-amp as an inverting amplifier, V
+
- V
-
= 0, this is because
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Open gain loop is very low
Closed loop gain is very high
Open loop gain is very high
Both (a) and (a)
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Question # 11
A diode characteristics curve is a plot between
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Current and resistance
Voltage and time
Voltage and current
Current and time
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Question # 12
the number of terminals in a semiconductor diode are
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2
3
4
5
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Question # 13
Base of transistor is of order:
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10
-11
m
10
6
m
10
-8
m
10
-6
m
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Question # 14
The circuit of full wave rectification consist of
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Three diodes
Four diodes
Two diodes
One diode
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Question # 15
For automatic Switching of streetlight, the op amplifier is used as.
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Inductor
Converter
Comparator
Thermistor
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Question # 16
LDR becomes necessary when op amp is used as a
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Night switch
Inverter
Comparator
Rectifier
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Question # 17
OR gate is represented by:
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X = A+B
X=A.B
X=A+B
X=A.B
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