11th Class ICS Mathematics Test Online With Answers

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11th Class ICS Mathematics Test Online

Sr. # Questions Answers Choice
1 -2 sin α sin ß = sin (α + ß) + sin (α - ß) cos (α + ß) + cos (α - ß) cos (α + ß) - cos (α - ß) cos (α - ß) + cos (α - ß)
2 2 cos α sin ß = cos (α + ß) + cos (α - ß) sin (α + ß) + sin (α - ß) sin (α + ß) - sin (α - ß) <div>cos (α + ß) + cos (α - ß)</div>
3 2 sin α cos ß = sin (α + ß) - sin (α - ß) cos (α + ß) + cos (α - ß) sin (α + ß) + sin (α - ß) cos (α + ß) - cos (α - ß)
4 1 + cos Θ 1 - cos Θ
5 If sin α = cos ß in any triangle ABC then: α + ß = 90° α + ß = 180° α + ß = 360° α + ß
6 Cot1°, Cot2°, Cot3°, .......... Cot89° = -1 1 none
7 tan (270° + Θ) is equal: cot Θ tan Θ -cot Θ -tan Θ
8 If an angle α is allied to an angle ß, then α ± ß = __________: 90° multiple of 90° 180° multiple of 180°
9 tan (-135°) = 0 1 √2
10 sec (2π + Θ), where Θ is a basic angle will have terminal side in: quad. I quad. II quad. III quad. IV
11 csc (2π - Θ), where Θ is a basic angle, will have terminal side in: quad. I quad. II quad. III quad. IV
12
13
14 - cot Θ - tan Θ tan Θ none of these
15 none of these
16 quad. I quad. II quad. III quad. IV
17 quad I quad. II quad. III quad. IV
18 sin (Θ - π) =
19 Tan (294°) = tan24° -tan24° cot24° -cot24°
20 A reference angle Θ is always:
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