Question # 1

Lyman series lie in

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Ultraviolet region

Visible region

Infrared region

Radio waves region

In discharge tube, properties of X-rays depend upon the nature of.

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Residual gas

Cathode plate

Anode plate

All of these

The wave number of the light emitted by a certain source is 2 x 10⁶m. the wavelength of this light is

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500 nm

500 m

200 nm

5 x 10⁷m

When fast neutron carries nuclear reaction with nitrogen it ejects aprticles.

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Alpha

Gamma

Beta

Nil

The nature of positive rays depends on

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The nature of electrode.

The nature of discharge tube

The nature of residual gas

All of the above

Bohr's model of atom is contradicted by

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Planck quantum theory

Quartization of energy of electrons

Heisenberg's uncertainty principle

Quartization of angular members

The mass of alpha particle is equal to.

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Four times the mass of one proton

That of one hydrogen atom

That of one electron

That of one proton

When 6d orbital is complete, the entering electron goes into.

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7f

7s

7p

7d

When 5d orbital is completed them entering electron goes into.

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6s

6p

6d

6f

Which of the following wave properties is inversely proportional to the energy for electromagnetic radiations

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Frequency

Wave number

Velocity

Wave length

The azimuthal quantum number / = 2, then M(Magnetic quantum number) can have values as

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+1, -1

+1, 0, -1

+2, +1, 0,1, -1, 2

+3, +2, +1, 0, 1, -2, -3

Quantum number values for 2p orbitals are

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n = 2, l = 1

n =1, 1 = 2

n =1, l = 0

n = 2, l = 0

Quantum number values for 3p orbitals are.

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n = 0, l = 3

n = 3 , l = 1

n = 2, l = 1

n = 2 , l = 3

Cathode rays cast shadow when an opaque object is placed in their path. This behavior of cathode rays show that.

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They move is straight line

They are negatively charge

They possess momentum

They are energetic

Transition from various energy levels to the lowest energy level gives.

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Lyman series

Balmer series

Panchen sereis

Pfund series

Which is not decay product of free neutron

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Proton

Electron

Neutron

Antineutrino

Which formula will be used to determine the number of in electrons sub shell of an atoms.

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2(l+1)

2(2l+1)

(l+1)

(2l+1)

The wave number of the light emitted by a certain source is 2 x 10⁶ m-1 . The wavelength of this light will be.

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500 nm

5000 nm

200 nm

5 x10⁷ m

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