Question # 1

The focus of the parabola x² = 4ay:

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(0, a)

(-a , 0)

(0, -a)

(a, 0)

The technique or method to find such a function whose derivative is given involves the inverse process of differentiation called:

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Differentiation

Integration

Differential

None of these

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x with respect to y

y with respect to y

y with respect to x

x with respect to x

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The point of intersection of the perpendicular bisectors of a triangle is called:

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Centroid

Ortho-center

Circums-center

In-center

Which are the following triples can be direction angles of a single vector:

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45°,45°,60°

30°,45°,60°

45°,60°,60°

30°,30°,30°

Point of intersection of x + y = 5 & x - y = 3 is:

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(5, 5)

(4, 2)

(4, 1)

(1, 4)

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a

b

c

a + b

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0

1

If the equation of the parabola is y2 = 4ax, then opening of the parabola is to the right of the:

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x-axis

y = x

y-axis

x + y =0

If (1, x) is the mid point of the line segment joining the points (1, 2) & (1, 6) then x =

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1

2

3

4

The radius of circle x² + y² + 2gx + 2fy + c = 0 is:

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The line y = c is above the x - axis, if:

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c > 0

c < 0

c = 0

A point of a solution region where two of its boundary lines intersects is called a __________ point of the solution region:

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Maximum

Corner

Minimum

None of these

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x - axis

z - axis

y - axis

None of these

tanh x =

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x = a

x = 2

x = 0

None

A null vector is defined as a vector whose magnitude is:

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1

2

0

None of these

Joint equation of y + 2x = 0, y - 3x = 0 is:

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(y+2x)(y-3x) = 0

(y-2x)(y-3x) = 0

(y+2x)(y+3x) = 0

(y-2x)(y+3x) = 0

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domain

range

lower limit

upper limit

If equation of circle is (x - h)² + (y - k)² = r², then center of a circle:

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(-h, -k)

(h, k)

(-h, k)

(h, -k)

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