Question # 1

If b²-4ac > 0, but not a perfect square then roots of ax²+bx+c=0 are:

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Imaginary

Rational

Irrational

None of these

Roots of the equation 4x²-4x+1=0 are:

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Real, equal

Real, uneqal

Imaginary

Irrational

If b²-4ac = 0, then roots are:

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Rationaland equal

Irrationaland equal

Irrationaland unequal

Rational and unequal

The product of roots, of equation 5x²+(7-2m) x + 3 = 0 will be:

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The nature of the roots of equation ax²+bx+c=0, is determined by:

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Sum of the roots

Product of the roots

Synthetic division

Discriminant

Synthetic division is simply a short cut of:

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H.C.F

L.C.M

Long division method

Factorization

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If 1 is the zero of polynomial, then remainder is:

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3

2

0

1

Sum roots of 4x²-3x+6=0:

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1

If b²-4ac>0 and is a perfect square, then roots are:

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Rational and equal

Rationaland unequal

Irrationaland equal

Irrationaland unequal

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P(Product of the roots)

S (Sum of the roots)

D (Difference of the roots)

R (Ratio of the roots)

The Discriminant of ax²+bx+c=0 is:

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b²-4ac

b²⁺4ac

-b²⁺4ac

-b²-4ac

If a = -2, b = -1 and c = -1, then discriminant is equal to:

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17

-17

-7

7

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1

0

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4

3

1

0

The value of i is equal to:

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The nature of roots depends on the value of:

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-b+4ac

b²+4c

b²-4ac

-b+4ac²

Find k, if the roots are equal in (k+3)x²-2(k+1)x-(k+1)=0:

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2, -1

-2,-1

-2,1

2,1

If (x+1)(7x+1) = 0 then x is equal to:

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