Question # 1

Shifting origin to (-3,2), the new coordinate of (-2,6) are:

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(1,4)

(2,4)

(-1,3)

(-1,4)

The points A, B and C are said to be collinear if they:

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be on same line

have same slope

Lie on a same plane

options a & b

The distance between lines 3x + 4y = 9 and 6x +8y = 15 is:

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2/3

3/10

8

6/5

The points (-1,3), (3,0) are the vertices of:

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Right-angled triangle

Isosceles triangle

Equilateral triangle

square

Three points (-2,2) (8,-2) and (-4,3) are vertices of a :

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Isosceles triangle

right-angled triangle

Equilateral trainagle

Rectangle

The in-centre of triangle whose vertices are (0,0), (5,12) and (16,12) is:

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(9,7)

(2,7)

(9,2)

(7,9)

The quadrilateral with the vertices (-3,-2), (2,-1), (3,4) and (-2,3) is a:

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Square

Rectangle

rhombus

parallelogram

If the points (a,b), (x,y) and (a-x, b-y) are collinear, then ay =

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bx

b-y

a-x

x

x-axis divides the line segment joining points (2,-3) and (5,6) in the ratio:

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2 : 1

-2 : 1

1 : 2

-1 : 2

The distance from the point P(6,-1) to the line 6x - 4x + 9 = 0 is:

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5/7

√52/7

2/48

49 /√52

If points (5 , 5), (10 , x) and (-5 , 1) are collinear, x =

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5

3

9

7

If the line is parallel to they y-axis, then m is said to be:

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zero

undefined

1/2

-1

If a point (p,q) is equidistant from the points (5,3) and (-2,-4), then p+ q =

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-1

1

3

-3

The distance of a point (x cosθ , x sinθ ) from origin is:

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x

x tanθ

-tanθ

-cotθ

In 𝜟ABC the mid points of AB and AC are (3,5) and -3,-1) respectively, then the length of the side BC is:

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15

10

30

20

The points (3,1), (-2,-3) and (2,2) are the vertices of :

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Equilateral triangle

Isosceles triangle

right -angled triangle

rhombus

In translation of axes,________is shifted to another point in the plane.

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a-axis

y-axis

origin

Point

Bisectors of angles of a triangle are:

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Collinear

Concurrent

Perpendicular

zero

Shifting origin to (1,-2), the new coordinates of (4,5) are:

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(3,7)

(5,3)

(-3,7)

(3,-7)

The distance between two parallel lines 2x - 5y + 13 = 0 and -2x +5y -6 = 0 is:

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√29

8/√29

7 /√29

29√7

The two vertices of a triangle are (-2,4)and (5,4). If its centroid is (5,6), then third vertex is:

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(-10,12)

(12,-10)

(12,10)

(10,12)

The two lines 5x + 7y = 35 and 3x -7y=21, intersect at the point:

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(7,5)

(1,2)

(2,7)

(7,0)

The points (a ,0),(0,b) and (3a , -2b) are:

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Collinear

Vertices of isosceles triangle

corner of a right-angled triangle

None of these

The length of perpendicular from (3,1) to the line 4x + 3y +20 = 0 is:

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7

5

11

12

The length of perpendicular form(-2,3) to the line y=2x-3 is:

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5√2

6

2√5

7.5

If points (-1 , h), (3,2) and (7,3) are collinear then h=

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3

4

0

None of these

Shifting origin to (-4,-6), the new coordinates of (-6,-8) are:

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(-1,2)

(-2,-2)

(1,-2)

(3.-2)

If (x,y) are the coordinates of a point P, then the first number of the ordered pair is called:

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Ordinate

Abscissa

quadrant

Cartesian

The slope of the line from B (2,-3) through A (0,3) is:

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-3

1/3

0

undefined

The cartesian system of coordinates was introduced by:

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Eulaer

Euclid

Descrates

Maclream

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