Question # 1

The mid point of the line segment joining the points (a,b) and (b,a) is

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For different values of k equation 4x+5y =k represents

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Parallel lines

Lines parallel to x -axis

Perpendicular lines

Lines parallel to y -axis

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0

1

-1

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The distance of the point (-2,3) from x-axis is

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-2

2

3

1

The distance between the points (0,0) and (x,y) is

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x²+ y²

x

y

If (2, 3) is the mid point of (a, 3) and (5, b) then

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a = 1 , b = -3

a = -1 , b = 3

a = 1 , b =3

a = -1 , b = -3

The equation of line passing through intersection of line x = 0 and y = 0 and the point (2,2) is

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y = x

y = x - 1

y = x + 1

The slope of y-axis is

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0

undefined

1

The equation of the sphere thro' the origin and making intercepts a, b, c on co-ordinate axes is

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x²+ y²+ z²+ ax + by + cz = 0

x²+ y²+ z²- 2ax - 2 by - 2 cz = 0

x²+ y²+ z²= a + b + c

x²+ y²+ z²- ax - by - cz =0

The points (5, 2, 4)(6, -1, 2) and (8, -7, k) are collinear if k is equal to

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-2

2

3

-1

The lines l1and l2intersect. The shortest distance between them is

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Positive

Negative

Zero

Infinity

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1

2

-1

0

The distance between the points (2, 2) and (3, 3) is

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10

5

2

The square of the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

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The distance of the point (-2 , -3) from y-axis is

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2

-2

3

-3

If A(x₁, y₁) , B(x₂, y₂) and C(x₃, y₃) are the vertices of a triangle then its centroid is

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For all points (x,y) in third quadrant

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x > 0 , y < 0

x > 0 , y > 0

x < 0 , y < 0

x < 0 , y > 0

The point of concurrency of the right bisectors of the sides of a triangle is called

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incentre

circum center

e-center

centroid

For all points (x,y) in second quadrant

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x > 0 , y < 0

x > 0 , y > 0

x < 0 , y < 0

x < 0 , y > 0

The slope of x-axis is

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0

undefined

1

The mid point of the line segment joining the points A(3,1) and B(-2,-4) is

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(1, -3)

The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is

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x + y + z - 15 = 0

x - y + z - 15 = 0

x - y - z - 15 = 0

x + y + z + 15 = 0

If distance of (a,b) from y-axis is 2 then

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a = 2

b = 2

a = b

a = 4

The distance between the points (0 , 0) and (1, 2) is

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5

0

3

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If l, m, n are the d.c.'s of a line, then

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l2+ m2+ n2= 0

l2+ m2+ n2= 1

l + m + n = 1

l = m = n = 1

The distance between two points P(x₁, y₁) and Q (x₂, y₂) is

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The foot of perpendicular from (α,β,γ) only y-axis is

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(α, 0, 0)

(0,β, 0)

(0, 0, γ)

(0, 0, 0)

A joint equation of the lines through the origin and perpendicular to the lines ax2 +2hxy +by2 =0 is indentical is ax2 +2hxy +by2 =0 if

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h2 = ab

a + b =0

a = b

a≠ b

a = b = 0

The mid point of the line segment joining the points (3,-1) and (-3,1) is

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(3,-1)

(0,0)

(2,2)

(4,4)

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