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ECAT Mathematics Chapter 16 Solution of Trigonometric Functions Online Test MCQs With Answers
Question # 1
cot
θ
= sin 2
θ
if
θ
=
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Question # 2
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Question # 3
The number of values of x in the interval [0, 5
π
] satisfying the equation 3 sin
2
x - 7 sinx + 2 = 0 is
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0
5
6
10
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Question # 4
By expressing sin 125° in terms of trigonometrical ratios, answer will be
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sin 65° = 0.9128
sin 55° = 0.8192
sin 70° = 0.5384
sin 72° = 0.1982
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Question # 5
The solution of the equation cos
2
θ
+ sin
θ
+ 1 = 0 lies in the interval
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Question # 6
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30°
45°
60°
75°
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Question # 7
The number of points of intersection of two curves y = 2 sin x and y = 5x
2
+ 2x + 3 is
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0
1
2
None of these
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Question # 8
The general value of
θ
satisfying the equation 2 sin
2
θ
- 3 sin
θ
-2 = 0 is
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Question # 9
For Cosine Rule of any triangle ABC, b
2
is equal to
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a
2
- c
2
+ 2ab cos A
a
3
+ c
3
- 3ab cos A
a
2
+ c
2
- 2ac cos B
a
2
- c
2
4bc cos A
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Question # 10
General solution of 1 + cos x = 0 is
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Question # 11
The smallest positive root of the equation tan x - x = 0 lies on
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Question # 12
One root of the equation cos x - x + 1/2 = 0 lies in the interval
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Question # 13
Sine rule for a triangle states that
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a/sin A = b/sin B = c/sin C
sin A/a = sin B/b = sin C/c
a/sin A + b/sin B + c/sin C
2a/sin A = 2b/sin B = 2c/sin C
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Question # 14
If sin (
π
cos
θ
) = cos (
π
sin
θ
), then which of the following is correct?
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Question # 15
The number of solution of the equation tan x + sec x = 2 cos x lying in the interval [0, 2
π
] is
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0
1
2
3
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Question # 16
If 4 sin
2
θ
=1, then values of
θ
are
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Question # 17
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From an empty set
1
2
>2
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Question # 18
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none of these
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Question # 19
cot
θ
= sin 2
θ
if
θ
=
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Question # 20
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I and
I
I quadrants
I
I and
I
I
I quadrants
I
I and
I
V
quadrants
none of these
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Question # 21
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No solution
One real solution
More than one real solution
None of these
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Question # 22
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A finite non-empty set
Null set
Both a and b
None of these
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Question # 23
The solution set of sin x + cos x = 0 is
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Question # 24
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Question # 25
The solution of the equation 3 tan
2
x = 1 is ____________
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none of these
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Question # 26
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none of these
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Question # 27
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Question # 28
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Question # 29
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Question # 30
By expressing cos 113° in terms of trigonometrical ratios, answer will be
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− cos 76° = -0.7093
− cos 65° = -0.4258
− cos 67° = -0.3907
− cos 62° = -0.8520
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