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ECAT Chemistry Online Test
| Sr. # | Questions | Answers Choice |
|---|---|---|
| 1 | 0.025 M 1.5 M 0.1 M .25 M | |
| 2 | A solution sucrose is 34.2%. The volume of solution containing one mole of solute : | 342<span style="font-family: Arial, sans-serif; font-size: 10.5pt;">cm</span><sup>3</sup><p class="MsoNormal"><o:p></o:p></p> 1000<span style="font-family: Arial, sans-serif; font-size: 10.5pt;">cm</span><sup>3</sup><p class="MsoNormal"><o:p></o:p></p> 500<span style="font-family: Arial, sans-serif; font-size: 10.5pt;">cm</span><sup>3</sup> 242<span style="font-family: Arial, sans-serif; font-size: 10.5pt;">cm</span><sup>3</sup> |
| 3 | (A) is one molar NaCl solution and (b) is 1 molal NaCl solutin : | A and B are of same strength. A is more Concentrate than B. b is more Concentrate than A. None of above. |
| 4 | A solution of glucose is 10% The volume to which 1g mole of it dissolved will be : | 8.1 dm<sup>3</sup><p class="MsoNormal"><o:p></o:p></p><p class="MsoNormal"><o:p></o:p></p> 1.7 dm<sup>3</sup><p class="MsoNormal"><o:p></o:p></p> 1.8 dm<sup>3</sup><p class="MsoNormal"><o:p></o:p></p> 6.1 dm<sup>3</sup><p class="MsoNormal"><o:p></o:p></p> |
| 5 | Molarity of pure water is : | 33.3 55.5 44.4 66.6 |
| 6 | To calculate volume of the solvent, we need to know, the : | Density of solute Normality of solute Mass of solute Molarity of solute |
| 7 | As compared to molar solution, in the molal solution the quantity of solvent is : | Comparatively lesser More or less equal Comparatively greater Very large |
| 8 | The number of moles of solute in 1000g (1 Kg) of the solvent is called : | Molarity Molarity Normality Mole fraction |
| 9 | The number of moles of solute dissolved per dm3 of the solution is called : | Normality. Molarity. Molarity. None of above. |
| 10 | In which type of following solutions the total volume of solutions may not be necessarily equal to sum of volumes of solute and solvent ? | Percentage volume/volume Percentage volume/weight Percentage weight/volume Percentage weight/weight |
| 11 | In which type of following solutions we don't know the total volume of the solutions : | Percentage weight/weight Percentage weight/volume Percentage volume/volume Percentage volume/weight |
| 12 | Solutions containing relatively lower concentrations of solute are called : | Concentrated solutions. Lighter solutions. Dilute solutions. None of above. |
| 13 | The substance which is present in large quantity is called a : | Solute Solvent solutiion None of Above |
| 14 | A solution is a homogeneous mixture of two or more kinds different : | Molecular. Covalent substance Ionic Substances Both (a) and (c) |
| 15 | Every sample of matter with uniform properties and a fixed composition is called a : | Solid Liquid. Phase. Gas. |
| 16 | Colligative properties are the properties of : | Dilute solutions which behave as nearly ideal solutions. Concentrated solutions which behave as nearly non-ideal solutions. Both(i) and (ii) Neither (i) nor (ii) |
| 17 | The molar boiling point constant is the ration of elevation in boiling point to : | Molarity Molarity Mole fraction of solvent Mole fraction of solute. |
| 18 | The solutions of NaCl and KCl are prepared separately by dissolving same amount of solute in water, which of the following statements is true fro these solutions ? | KCl solution will have higher boiling point than NaCl solution. Both the solutions have same boiling points. KCl and NaCl solutions possess same vapour pressure. KCl solution possesses lower freezing point than NaCl solution. |
| 19 | Which of the following solutions has the highest boiling point ? | 5.85% solution of sodium chloride. 18.0% solution of glucose. 6.0% solution of urea. All have same boiling points. |
| 20 | An azeotropic mixture showing it's positive deviation from Raoult's law, the volume of the mixture is : | Slightly more than the total volume of the components. Slightly less than the total volume of the components. Equal to the total volume of the components. None of these. |
| 21 | An azeotropic mixture of two liquids boils at a lower temperature than either of them when : | It is saturated. It shows positive deviation from Raoult's law. It show negative deviation from Raoult's law. It is metastable. |
| 22 | A solution of glucose is of methanol in water has vapor pressure : | Equal that of water. Equal to that of methanol. More than that of water. Less than that f water. |
| 23 | 18 g glucose is dissolved in 90 g of water. The relative lowering vapor pressure is equal to : | 1/5 5.1 1/51 6 |
| 24 | N2 +3H2⇌
2NH3 + Heat for above equation, the |
Low temperature at high pressure. High temperature and low pressure. High temperature and high pressure. Low temperature at low pressure. |
| 25 | The substance which increases rate of reaction but remains unchanged at the end of reaction is called : | Catalyst. Indicator. Promoter. Activator. |
| 26 | N23H2⇌ 2NH3 Which of the following change will favorthe formation of moreNH3at equilibrium in above reaction : |
By adding NH<sub>3.</sub> By removing<span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">H</span><sub>2.</sub> By decreasing pressure. By increasing pressure. |
| 27 | Extent to H2 + L2 à2Hl can be increased by
: |
<p class="MsoNormal">Increasing temperature.<o:p></o:p></p> <p class="MsoNormal">Increasing product. <o:p></o:p></p> <p class="MsoNormal">Increasing pressure. <o:p></o:p></p> <p class="MsoNormal">Adding a catalyst.<o:p></o:p></p> |
| 28 | 2SO2+ O2⇌2SO2H= 188KJ mole-1
Which statement about following equilibrium is correct : |
<p class="MsoNormal"><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">The value of</span>K<sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif;">p</span></sub>falls with arise in temperature.<o:p></o:p></p> <p class="MsoNormal"><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">The value of</span>K<sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif;">p</span></sub>is equal tok<sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif;">c.</span><o:p></o:p></sub></p> <p class="MsoNormal"><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">The value of</span>K<sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif;">p</span></sub>falls with the increase pressure.<o:p></o:p></p> <p class="MsoNormal"><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">Adding V</span><sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif;">2</span></sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">O</span><sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif;">5</span></sub><span style="font-size: 10.5pt; line-height: 107%; font-family: Arial, sans-serif; background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;">catalyst increase the equilibrium yield of Sulphur trioxide.</span><o:p></o:p></p> |
| 29 | 2SO2 + O2 ⇌ 2SO2 H= 188KJ mole-1 |
The value of<span style="font-size:11.0pt;line-height:107%; font-family:"Calibri",sans-serif;mso-ascii-theme-font:minor-latin;mso-fareast-font-family: Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi; mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">K<sub>p</sub>falls with arise in temperature.</span> The value of<span style="font-family: Calibri, sans-serif; font-size: 11pt; line-height: 15.6933px;">K<sub>p</sub>is equal to</span><span style="font-size:11.0pt;line-height:107%; font-family:"Calibri",sans-serif;mso-ascii-theme-font:minor-latin;mso-fareast-font-family: Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi; mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">k<sub>c.</sub></span> The value of<span style="font-family: Calibri, sans-serif; font-size: 11pt; line-height: 15.6933px;">K<sub>p</sub>falls with the increase pressure.</span> Adding V<sub>2</sub>O<sub>5</sub> catalyst increase the equilibrium yield of Sulphur trioxide.<p class="MsoNormal"><o:p></o:p></p> |
| 30 | A large value of Kcmeans that at equilibrium : | Less reactant and more products. Reactants and product in same amounts. More reactants and less products. None of above. |
