Question # 1

How many allotropic forms are present in carbon

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Two

Three

Four

Five

The paramagnetic behaviour of oxygen is well explaned on the basis of.

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M.O Theory

N.B Theory

VSEPR Theory

CF theory

Sum of pKa and pKb is equal to.

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1

7

0

14

Which is not use of liquid crystals.

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Temperature sensor

Liquid crystal display

Skin thermography

Energy supply in electrical devices.

The azimuthal quantum number / = 2, then M(Magnetic quantum number) can have values as

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+1, -1

+1, 0, -1

+2, +1, 0,1, -1, 2

+3, +2, +1, 0, 1, -2, -3

pKa of CH3COOH is 4.74. The pKb value of CH3COO- ions will be

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7

14

9.26

zero

What is the mass of aluminium is 204 g of the aluminum oxide Al2O3.

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26 g

27 g

54 g

108 g

Forces of attraction between He atoms are.

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Hydrogen bonding

London forces

Debye forces

Ion dipole forces

A negative deviation from Raoult's law in solution means, the solution has

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High boiling point and high vapour pressure

High boiling point and low vapour pressure

Low boiling point and low vapour pressure

Low boiling point and high vapour pressure

Dilatometer method is useful for the reactions that involve.

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Ionic species

Where reactant absorb U.V. visible or infrared radiations

Small volume changes in solutions

Change in refractive indices

Pressure remaining constant, at which temperature the volume of a gas will become twice of what it is at 0 ^oC

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546 ^oC

200 ^oC

546 K

273 K

The unit of Kc for the reaction N2 +O2 = 2NO will be

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mol dm-3

mol-1 dm+3

mol-2 dm+6

No units

Oxidation number of Cr in a C₂CrO₄ is

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+2

+4

+6

+8

London dispersion force are the only forces present among the.

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Molecules of water in liquid state

Atoms of helium in gaseous state at high temperature

Molecule of solid iodine

Molecules of hydrogen chloride gas

Nickel has isotopes

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3

5

6

11

The largest number of molecule are present.

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3.6 g of H2O

4.6 g of C2H5OH

2.8 g of CO

5.4 g of N2O5

Quantum number values for 2p orbitals are.

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n = 2, 1 =1

n =1, 1 = 2

n =1, 1= 0

n = 2, 1 = 0

If absolute temperature of gas is doubled and the pressure is reduced to one half, the volume of the gas will.

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Remain unchanged

Increase four times

Reduce to 1/4

Be doubled

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