| 1 |
To find the sum of given values whose average is knowsn, the following formula is used. |
sum of item = average of item + number of item
sum of item= average of item-number
sum of items = average of item x number of items
None of these
|
| 2 |
If a student got 19,21,22,24,and 19 marks is different subjects is the monthly test. his average marks will be. |
19
21
22
25
|
| 3 |
The average of a nuber of items can be found by. |
Dividing sum of items by nuber of items
Adding sum of items and numebr of items
Multiplying sum of items by number of itmes
Subtracting sum of items from number of item
|
| 4 |
1 day =---------------- weeks. |
7
1/7
30
12
|
| 5 |
4 x length of a side = |
Perimeer of triangle
Perimeter of Circle
Perimeter rectangle
Perimeter of square
|
| 6 |
The perimeter of a rectangle is 128 cm, its lengthis 45 cm, What willbe its width. |
10 cm
14 cm
15 cm
25 cm
|
| 7 |
If the area of a square is 121 cm3 then its perimeter willbe. |
144 cm
11 cm
44 cm
88 cm
|
| 8 |
Whcih of the following is not the unit of area. |
cm3
m2
km3
km
|
| 9 |
The length of a squre shsped field is 20 m then its perimeter will be. |
40 cm
60 cm
80 cm
100 cm
|
| 10 |
The area of a square is 144 cm3, Find he length of its one side. |
12 cm
16 cm
288 cm
20 cm
|
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